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It must be brought to a stop in 26.0 s. (a) How much work must be - 15587224 2013-10-24 · pierrot bules. Lv 7. 7 years ago. Favorite Answer. http://hyperphysics.phy-astr.gsu.edu/hbase/imgmec/ I = m R^2 = 28 * 1.03 ^2 = 29.7052 kg m 2. ω = 280 / 60 * 2π= 29.3215 rad /s.

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It must be brought to a stop in 15.0 s. (a)How much work must be done to stop it? Transcribed Image Textfrom this Question. A 32.0 kg wheel, essentially a thin hoop with radius 1.20 m, is initially rotating at 280 rpm.

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It must be brought to a stop in 15.0 s. (a) How much work must be done to stop it? 2009-07-02 A 32 kg wheel, essentially a thin hoop with radius 1.2m, is rotating at 280 rev/min. It must be brought to a stop in 15s. A 32 kg wheel, essentially a thin hoop with radius 1.2m, is rotating at 280 rev/min. It must be brought to a stop in 15s.

The potter can stop the wheel in 6.0 s by pressing a wet rag against the rim and exerting a . math.
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Favorite Answer. http://hyperphysics.phy-astr.gsu.edu/hbase/imgmec/ I = m R^2 = 28 * 1.03 ^2 = 29.7052 kg m 2.

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It must be brought to a stop in 15s. - Answered by a verified Tutor. Transcribed Image Textfrom this Question. A 32.0 kg wheel, essentially a thin hoop with radius 1.20 m, is initially rotating at 280 rpm.

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Initially the axle of the spinning wheel is horizontal, and the wheel is suspended only from the string. At what rate will the A wheel of radius 24.7 cm, moving initially at 43.3 m/s, rolls to a stop in 225 m. Calculate (a) its linear acceleration and (b) its angular acceleration. (c) The wheel's rotational inertia is 0.155 kg· m 2 Calculate the torque exerted by rolling (a) Find the rotational inertia of the wheel about its central axis. The rotational inertia of a cylindrical disk is given by I = 1 2 MR2 I = 1 2 24.8 kg( 0.233 m)2 I = 0.673 kg ·m2 (b) When the grinding wheel’s motor is turned oﬀ, friction causes the wheel to slow from 1200 rpm to rest in 59.8 s.

3.0. 27.2. If the tie is to be loaded with, for example, 53 kg this produces: Minimum tensile strength 7.6. 150.0. 32.0. 225.